(x-1)(x+2)(x-1)=8x^2-x

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Solution for (x-1)(x+2)(x-1)=8x^2-x equation: 



(x-1)(x+2)(x-1)=8x^2-x

We move all terms to the left:

(x-1)(x+2)(x-1)-(8x^2-x)=0

We get rid of parentheses

-8x^2+(x-1)(x+2)(x-1)+x=0

We multiply parentheses ..

-8x^2+(+x^2+2x-1x-2)(x-1)+x=0

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